q=%28%E8%8B%B1%29%E4%BA%9A%E5%8E%86%E5%B1%B1%E5%A4%A7%C2%B7H.+%E5%93%88%E8%80%83%E7%89%B9%28Alexander+H.+Harcourt%29&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
(英)亚历山大·H. 哈考特(Alexander H. Harcourt)